Pis’ma v ZhETF, vol. 111, iss. 7, pp. 462 - 463
© 2020
April 10
Amplitude of waves in the Kelvin-wave cascade
V. B. Eltsov+1), V. S. L’vov
+Department of Applied Physics, Aalto University, POB 15100, FI-00076 AALTO, Finland
Department of Chemical Physics, Weizmann Institute of Science, 76100 Rehovot, Israel
Submitted 5 March 2020
Resubmitted 5 March 2020
Accepted 5 March 2020
DOI: 10.31857/S0370274X20070061
In quantum turbulence, velocity fluctuations and
Ekw =
νsLk = L
νsA2kk2 =
vortex reconnections drive oscillating motion of quan-
k=±kmin
k=kmin
tized vortices - Kelvin waves [1]. Kelvin waves inter-
νs
act non-linearly and support a cascade of energy to-
=L
A2kk2 dk.
(3)
k
wards smaller length scales and larger wave numbers [2].
min kmin
The theory of the Kelvin-wave cascade was the subject
Comparing this result to the expression of the energy
of controversy, until finally the L’vov-Nazarenko model
via the Kelvin-wave frequency ωk and the combined oc-
[3, 4] got supported by numerical simulations [5, 6]. Re-
cupation number Nk for modes with ±k [4]
cently, progress in experimental techniques [7-9] enables
controllable excitation of waves on nearly straight vor-
κΛ
Ekw = ρsL
Ek dk, Ek = ωkNk, ωk =
k2,
tices and potential observation of the Kelvin-wave cas-
kmin
cade. In this work we provide relation of the energy flux
(4)
carried by the cascade to the amplitude of the excited
we find
kmin
Kelvin waves, which is important for analysis of such
A2k =
Nk.
(5)
κ
experiments.
The L’vov-Nazarenko spectrum is [4]
We assume that the Kelvin-wave cascade on a vortex
of length L (cm) carries the energy flux ǫ (erg/s) and
κΛǫ1/3
starts from the wave number kmin (cm-1). Our goal is
Ek = CLN
,
CLN ≈ 0.304,
(6a)
Ψ2/3k5/3
to find the amplitude Ak (cm) of the Kelvin wave with
the wave number k (cm-1). We start by noting that in
Ψ=
Ekdk.
(6b)
Λκ2
kmin
the local induction approximation the energy of a vor-
tex line Ev is given by the product of its length L and
Here ǫ is the energy flux per unit length and per unit
the vortex tension νs
mass. It is related to the flux ǫ as
)
ǫ
cm4
κ2Λ
( ℓ
ǫ=
,
[ǫ] =
(7)
Ev = νsL, νs = ρs
,
Λ = ln
(1)
s
s3
a0
Solving Eq. (6) for Ψ we get
Here ρs is the superfluid density, κ is the circulation
quantum, a0 is the vortex core radius and ℓ is the mean
(12πCLN)3/5ǫ1/5
intervortex spacing or the size of the enclosing volume,
Ψ=
(8)
κ3/5k2/5
min
in the case of a single vortex. For a spiral Kelvin wave of
the radius Ak and wavelength λk = 2π/k, the increase
and from Eq. (5) finally
of the length compared to that of the straight vortex is
(√
)
(2π3C3LN )1/5 k19/15minǫ1/5
A2k = 2
L
2A2k
9
κ3/5k11/3
Lk = λ2k + (2πAk)2 - λk
≈L
,
(2)
λk
λ2
(
)1/5
k
19/15
k
ǫ
min
≈ 1.4
(9)
where we assumed that Ak ≪ λk. Thus the total energy
κ3/5k11/3s
due to Kelvin waves is
Note that Ak ∝ ǫ1/10. Thus determination of the ampli-
1)e-mail: vladimir.eltsov@aalto.fi
tude from the energy flux should be relatively reliable,
462
Письма в ЖЭТФ том 111 вып. 7 - 8
2020
Amplitude of waves in the Kelvin-wave cascade
463
while the reverse procedure is bound to be very uncer-
Together with Eq. (11) this results in
tain.
Lkw
The total increase of the vortex line length due to
〈tan2 θ(z)〉 ≃ 2
= Ψ,
(15)
L
Kelvin waves can be found from the energy as Lkw =
= Ekws, where Ekw is given by Eqs. (4), (6a) and
where Ψ is given by Eq. (8).
(8):
To conclude, we have found the dependence of the
1/5
Ekw
21/5(3πCLN)3/5ǫ
amplitude of the Kelvin waves, of the length increase of
Lkw =
=L
(10)
νs
the vortex, and of the average vortex tilt on the energy
κ3/5k2/5
min
flux carried by the Kelvin-wave cascade. The results are
Thus for the relative increase we get a simple formula
applicable in the regime of weak turbulence of Kelvin
Lkw
Ekw
Ψ
=
=
(11)
waves, which is uniform along the vortex. We stress that
L
Ev
2
the amplitude of the Kelvin waves, generated when a
In cases, where instead of a single vortex, one con-
vortex is mechanically agitated, does not necessary co-
siders a vortex array with the total length L occupy-
incide with the amplitude of the motion of the agitator.
ing volume V with the density L = L/V
= ℓ-2, it
Solving the problem of excitation of Kelvin waves in a
might be more convenient to operate with the standard
realistic experimental geometry remains a task for fu-
3-dimensional energy flux ε = ǫL per unit mass and unit
ture research.
volume, [ε] =cm2 s-3. Then for the increase Lkw of the
The work has been supported by the European
vortex-line density due to Kelvin waves, we find using
Research Council (ERC) under the European Union’s
Eqs. (8) and (11)
Horizon
2020
research and innovation programme
(Grant Agreement # 694248).
)1/5
Lkw
Ψ
[2(3πCLN)3ε]1/5
( ε
=
=
≈ 2.2
,
Full text of the paper is published in JETP Letters
L
2
b2L2κ3
b2L2κ3
(12)
journal. DOI: 10.1134/S0021364020070012
where we introduced
b = kminℓ ∼ 1.
(13)
1. W. F. Vinen, Philos. Trans. R. Soc. A 366, 2925 (2008).
We note that the numerical value of the prefactor in
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Eqs. (9) and (12) should be taken with caution. In the
(2004).
calculations we assume that the total energy of Kelvin
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(2010) [JETP Lett. 91, 428 (2010)].
waves can be found by the integral (4) limited from be-
4. L. Boué, R. Dasgupta, J. Laurie, V. S. L’vov,
low by kmin with the scale-invariant spectrum (6). In
S. V. Nazarenko, and I. Procaccia, Phys. Rev. B 84,
reality this spectrum was derived for k ≫ kmin while
064516 (2011).
the main contribution to Ekw is coming from the re-
5. G. Krstulovic, Phys. Rev. E 86, 055301 (2012).
gion k ≃ kmin. Behavior of the Kelvin-wave spectrum
6. A. W. Baggaley and J. Laurie, Phys. Rev. B 89, 014504
in this long-wavelengths region may be different and, in
(2014).
general, is not universal.
7. A. M. Guénault, A. Guthrie, R. P. Haley, S. Kafanov,
In some applications, the tilt θ of a vortex carry-
Yu. A. Pashkin, G. R. Pickett, M. Poole, R. Schanen,
ing Kelvin waves with respect to the direction of the
V. Tsepelin, D.E. Zmeev, E. Collin, O. Maillet, and
straight vortex is of interest. The averaged tilt angle
R. Gazizulin, Phys. Rev. B 100, 020506(R) (2019).
can be connected to the length increase
8. C. S. Barquist, W. G. Jiang, P. Zheng, Y. Lee, and
L
H. B. Chan, J. Low Temp. Phys. 196, 177 (2019).
1
Lkw =
1 + tan2 θ(z)dz-L ≃
〈tan2 θ(z)〉L. (14)
9. T. Kamppinen and V. B. Eltsov, J. Low Temp. Phys.
2
0
196, 283 (2019).
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2020